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Asked: May 10, 20262026-05-10T15:20:32+00:00 2026-05-10T15:20:32+00:00

This isn’t legal: public class MyBaseClass { public MyBaseClass() {} public MyBaseClass(object arg) {}

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This isn’t legal:

public class MyBaseClass {   public MyBaseClass() {}   public MyBaseClass(object arg) {} }   public void ThisIsANoNo<T>() where T : MyBaseClass {   T foo = new T('whoops!'); } 

In order to do this, you have to do some reflection on the type object for T or you have to use Activator.CreateInstance. Both are pretty nasty. Is there a better way?

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  1. 2026-05-10T15:20:33+00:00Added an answer on May 10, 2026 at 3:20 pm

    You can’t constrain T to have a particular constructor signature other than an empty constructor, but you can constrain T to have a factory method with the desired signature:

    public abstract class MyBaseClass {     protected MyBaseClass() {}     protected abstract MyBaseClass CreateFromObject(object arg); }  public void ThisWorksButIsntGreat<T>() where T : MyBaseClass, new() {     T foo = new T().CreateFromObject('whoopee!') as T; } 

    However, I would suggest perhaps using a different creational pattern such as Abstract Factory for this scenario.

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