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Home/ Questions/Q 7440271
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T10:49:33+00:00 2026-05-29T10:49:33+00:00

This isn’t working the way I expect it to. Sample input will include an

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This isn’t working the way I expect it to. Sample input will include an asterisk that will resemble ether 0 or 1. The rest is comparing to see if the numbers match up. When I try to see if a character an asterisk it doesn’t work the way I expect it to.

Samples:

org = *01

bit = 001 || 101 || 011

public static void doesItWork(String org, String bit)
    {
        for(int i = 0; i <= org.length() - 1; i++)
        {
            System.out.println(org.substring(i, i + 1));
            if(org.substring(i, i + 1) != "*" && org.substring(i, i + 1) !=  bit.substring(i, i + 1))
                break;

            if(i == org.length() - 1)
                System.out.println(bit);
        }
    }

Thanks guys for your help.

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  1. Editorial Team
    Editorial Team
    2026-05-29T10:49:34+00:00Added an answer on May 29, 2026 at 10:49 am

    != on Strings doesn’t do what you want it to do. Java String.equals versus == explains, but in brief,

    org.substring(i, i + 1) != "*"
    

    should probably be

    !org.substring(i, i + 1).equals("*")
    

    or ideally

    org.charAt(i) != '*'
    
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