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Home/ Questions/Q 6938473
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T12:29:54+00:00 2026-05-27T12:29:54+00:00

This jQuery function is meant to post the value of num to a PHP

  • 0

This jQuery function is meant to post the value of num to a PHP page and then echo it in the correct status class, any ideas why nothing is happening, I have downloaded jQuery and called the file further up (not displayed here)

Any help is appreciated thanks!

<script>
 var num = 1;
                function ajax_post(){ 
$.ajax('javas.php', {
success: function(response) {
      $(".status").html(response);
}, 
data: "num=" + (++num)
});
}

function ajax_posta(){
$.ajax('javas.php', {
success: function(response) {
      $(".status").html(response);
}, 
data: "num=" + (--num)
});
}

$(document).ready(function() {
$('.eventer > .button').click(function () {
    ajax_post();
});
alert("lol");
});


</script>

This is what i have, this is my php code concerning the classes.

<div id = 'eventcontainer' >

<?php

//Getting posts from DB

$event1 = mysql_query("SELECT post,date,memid FROM postaction WHERE memid = '$id' ORDER BY date DESC LIMIT 5;");

while ($row1 = mysql_fetch_array($event1))
{




$event = $row1['post'];
$timeposted = $row1['date'];

$eventmemdata = mysql_query("SELECT id,firstname FROM users WHERE id = '$id' LIMIT 1");

while($rowaa = mysql_fetch_array($eventmemdata))
{
    $name = $rowaa['firstname'];
    $eventlist = "$event <br> $name";
}

echo " <div class = 'eventer'> $timeposted <br>$eventlist <input name='myBtn'       type='submit' value='increment' onClick='javascript:ajax_post();'>
<input name='lol' type='submit' value='dec' onClick='javascript:ajax_posta();'></div>
<div class = 'status'></div>";
echo "<br>";

}


?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:29:55+00:00Added an answer on May 27, 2026 at 12:29 pm

    Instead of $.post change it to $.ajax

    You could re-arrange the parameters to get it to work with $.post, but it looks like the code you have is meant to be run with $.ajax.

    Also, inside of here

    $(document).ready(function() {
        $('.eventer > .button').click(function () {
            var self = this;
            $.post('javas.php', function (data) {
                $(self).closest('.eventer').find('.status').html(data);
            })
        });
        alert("lol");
    });
    

    Are you sure you didn’t mean:

    $(document).ready(function() {
        $('.eventer > .button').click(function () {
            ajax_post();
        });
        alert("lol");
    });
    
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