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Home/ Questions/Q 8441453
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T08:33:53+00:00 2026-06-10T08:33:53+00:00

This link from the Gson project seems to indicate that I would have to

  • 0

This link from the Gson project seems to indicate that I would have to do something like the following for serializing a typed Map to JSON:

    public static class NumberTypeAdapter 
      implements JsonSerializer<Number>, JsonDeserializer<Number>,
InstanceCreator<Number> {

    public JsonElement serialize(Number src, Type typeOfSrc, JsonSerializationContext
context) {
      return new JsonPrimitive(src);
    }

    public Number deserialize(JsonElement json, Type typeOfT,
JsonDeserializationContext context)
        throws JsonParseException {
      JsonPrimitive jsonPrimitive = json.getAsJsonPrimitive();
      if (jsonPrimitive.isNumber()) {
        return jsonPrimitive.getAsNumber();
      } else {
        throw new IllegalStateException("Expected a number field, but was " + json);
      }
    }

    public Number createInstance(Type type) {
      return 1L;
    }
  }

  public static void main(String[] args) {
    Map<String, Number> map = new HashMap<String, Number>();    
    map.put("int", 123);
    map.put("long", 1234567890123456789L);
    map.put("double", 1234.5678D);
    map.put("float", 1.2345F);
    Type mapType = new TypeToken<Map<String, Number>>() {}.getType();

    Gson gson = new GsonBuilder().registerTypeAdapter(Number.class, new
NumberTypeAdapter()).create();
    String json = gson.toJson(map, mapType);
    System.out.println(json);

    Map<String, Number> deserializedMap = gson.fromJson(json, mapType);
    System.out.println(deserializedMap);
  }

Cool and that works, but it seems like so much overhead (a whole Type Adapter class?). I have used other JSON libraries like JSONLib and they let you build a map in the following way:

JSONObject json = new JSONObject();
for(Entry<String,Integer> entry : map.entrySet()){
     json.put(entry.getKey(), entry.getValue());
}

Or if I have a custom class something like the following:

JSONObject json = new JSONObject();
for(Entry<String,MyClass> entry : map.entrySet()){
 JSONObject myClassJson =  JSONObject.fromObject(entry.getValue());
     json.put(entry.getKey(), myClassJson);
}

The process is more manual, but requires way less code and doesn’t have the overhead of haivng to create a custom Type Adapter for Number or in most cases for my own custom class.

Is this the only way to serialize a map with Gson, or has anyone found a way that beats out what Gson recommends in the link above.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T08:33:54+00:00Added an answer on June 10, 2026 at 8:33 am

    Only the TypeToken part is neccesary (when there are Generics involved).

    Map<String, String> myMap = new HashMap<String, String>();
    myMap.put("one", "hello");
    myMap.put("two", "world");
    
    Gson gson = new GsonBuilder().create();
    String json = gson.toJson(myMap);
    
    System.out.println(json);
    
    Type typeOfHashMap = new TypeToken<Map<String, String>>() { }.getType();
    Map<String, String> newMap = gson.fromJson(json, typeOfHashMap); // This type must match TypeToken
    System.out.println(newMap.get("one"));
    System.out.println(newMap.get("two"));
    

    Output:

    {"two":"world","one":"hello"}
    hello
    world
    
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