Question

This may be impossible, but I was wondering if its possible to output the content of a define using the value of a variable.

Like this:

define("SEO_HOME", "Home name");
$var="SEO_HOME";
echo $var

This will print off course “SEO_HOME”. How can I make it print “Home name” (using the variable $var)?

Edit: Corrected define.

Edit:
My all problem his, the site I’ll edit use defines to identify all pages, eg:

define("CONTACT_PAGE","Please contact us");
define("INFO_PAGE","Some information about us");

And I’ll need to add custom html title on those pages, that owner will be able to edit. So I was thinking I would create a DB table with (id, page, title) where page would have CONTACT_PAGE, INFO_PAGE, etc. and title would be the title itself.

Now to make an edit page for site owner, I’ll have this:

//This would be an while mysql_fetch_assoc and not a multidimentional array, but for example this will work
$titleArray=array(array("CONTACT_PAGE", "my title for contact page"),array("INFO_PAGE", "my title for info page"));
?>
<tr>
    <td>Set title for: <?php echo $titleArray[0][0];?></td> 
    <td><input type="text" name="name" value="<?php echo $titleArray[0][1];?>" /></td>
</tr>
<tr>
    <td>Set title for: <?php echo $titleArray[1][0];?></td> 
    <td><input type="text" name="name" value="<?php echo $titleArray[1][1];?>" /></td>
</tr>

This shows on first td -> Set title for: CONTACT_PAGE

And I wanted it to show -> Set title for: Please contact us

Hope this clarifies my doubt.

Answer 1

you can use constant function:

 mixed constant ( string $name )

Return the value of the constant indicated by name.

constant() is useful if you need to retrieve the value of a constant,
but do not know its name. I.e. it is stored in a variable or returned
by a function.

This function works also with class constants.

<?php
define("SEO_HOME", "Home name");
$var="SEO_HOME";
echo constant($var);