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Home/ Questions/Q 7044807
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T02:27:13+00:00 2026-05-28T02:27:13+00:00

This may either be a silly question or i’ve searched for the wrong words:

  • 0

This may either be a silly question or i’ve searched for the wrong words:
I have a ComboBox and want to display doubles using a custom converter (showing the equivalent fraction).
In the DataTemplate i have to specify a DataType, which is Double, but i don’t know how to specity it. I’m sure there is a simple way to do so!

Adding the System-namespace to the window doesn’t compile

<Window ... xmlns:sys="clr-namespace:System" ...>

Simply typing Double or System.Double in DataType doesn’t either.

And defining a ViewModel for a simple Double-Type can’t be the solution either, can it?!

This is my code so far:

<ComboBox ItemsSource="{Binding Gains}" SelectedItem="{Binding Gain, Mode=TwoWay}">
    <ComboBox.Resources>
        <DataTemplate DataType=" ??????? fract">
            <TextBlock Text="{Binding ., Converter=fractConverter}"/>
        </DataTemplate>
    </ComboBox.Resources>
</ComboBox>

FULL SOLUTION:

Using the System namespace as sys: works!
Gains is a List<Double>
Gain is a Double

<Window ... xmlns:sys="clr-namespace:System;assembly=mscorlib" ...>

The Combobox works like this:

<ComboBox ItemsSource="{Binding Gains}" SelectedItem="{Binding Gain, Mode=TwoWay}">
    <ComboBox.Resources>
        <DataTemplate DataType="{x:Type sys:Double}">
            <TextBlock Text="{Binding ., Converter={StaticResource realConverter}}"/>
        </DataTemplate>
    </ComboBox.Resources>
</ComboBox>
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  1. Editorial Team
    Editorial Team
    2026-05-28T02:27:14+00:00Added an answer on May 28, 2026 at 2:27 am

    Like this:

     <DataTemplate DataType="{x:Type sys:Double}">
    
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