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Home/ Questions/Q 7945021
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T00:43:48+00:00 2026-06-04T00:43:48+00:00

This may seem like a simple question, but I can’t find the definite answer:

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This may seem like a simple question, but I can’t find the definite answer:

Say I have three servers on a local un-firewalled network, one of which is the registry (R) and the other two are clients (A and B), and Client A and B both connect to the registry.

Client A obtains a reference to an exported object on B via the registry and invokes a method – does that method call go through the registry? i.e. if A passes a large byte array to B as a parameter to a method call, does that take 2 hops via R, or does the registry tell A that B can be communicated with directly?

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  1. Editorial Team
    Editorial Team
    2026-06-04T00:43:50+00:00Added an answer on June 4, 2026 at 12:43 am

    No, calls from client to server to not pass through the RMI registry. The registry is only used to look up the reference to the server. Subsequent calls to the server go there directly.

    The RMI registry is really nothing more than an RMI server itself, which accepts and stores remote stubs for servers which register with it. It provides a known point-of-entry for clients who don’t know where to find the server. It hands the RMI stub back to the client, and the client then talks direct to the server via that stub.

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