Question

This may sound confusing, but how can you pass MULTIPLE ARGUMENTS in one ARGUMENT.

What I’ve tried is the following:

#define CALL(v, look, param, expect) v(param){look(expect);}

Example when using it (Doesn’t work):

void CALL(InitD3D, engine->InitD3D, (HWND hWnd, bool windowed), (hWnd, windowed))

// Which should give(i want it to):
// void InitD3D(HWND hWnd, bool windowed){engine->InitD3D(hWnd, windowed);}
// But it may give: InitD3D((HWND hWnd, bool windowed)){engine->InitD3D((hWnd, windowed));}
// Or something similar or not...

So is basic words, how can i pass multiple arguments in one argument, without screwing it up…

Thank You

Answer 1

#define CALL(v, look, param, expect) v param {look expect;}

namespace foo {
  void bob(int x, int y) {}
}
CALL(void bob, foo::bob, (int x, int y), (x,y))

int main() {
  bob(7,2);
}

I would advise against this technique.