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Home/ Questions/Q 7078401
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T06:32:35+00:00 2026-05-28T06:32:35+00:00

This Microsoft support page shows that there is no Win32 equivalent to C Run-Time’s

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This Microsoft support page shows that there is no Win32 equivalent to C Run-Time’s isdigit().

But there is IsCharAlphaNumeric and IsCharAlpha.

Intuitively, this leads me to:
IsCharAlphaNumeric() && !IsCharAlpha() is equivalent to (the non-existent) IsCharNumeric()

But I may be missing something…

Can I safely assume that the above is correct?

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  1. Editorial Team
    Editorial Team
    2026-05-28T06:32:36+00:00Added an answer on May 28, 2026 at 6:32 am

    Without knowing the semantics of IsCharAlphaNumeric() and IsCharAlpha(), there’s no way to determine whether

    IsCharNumeric(c) == (IsCharAlphaNumeric(c) && !IsCharAlpha(c))
    

    holds for all c. And it might be reasonable that it doesn’t hold, for example hexadecimal digits can be both, numeric and alphabetic.

    In other words, you can not safely assume the equivalence.

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