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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T16:39:03+00:00 2026-05-25T16:39:03+00:00

This might be a beginner question and understanding how cout works is probably key

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This might be a beginner question and understanding how cout works is probably key here. If somebody could link to a good explanation, it would be great.
cout<<cout and cout<<&cout print hex values separated by 4 on a linux x86 machine.

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  1. Editorial Team
    Editorial Team
    2026-05-25T16:39:03+00:00Added an answer on May 25, 2026 at 4:39 pm

    cout << cout is equivalent to cout << cout.operator void *(). This is the idiom used before C++11 to determine if an iostream is in a failure state, and is implemented in std::ios_base; it usually returns the address of static_cast<std::ios_base *>(&cout).

    cout << &cout prints out the address of cout.

    Since std::ios_base is a virtual base class of cout, it may not necessarily be contiguous with cout. That is why it prints a different address.

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