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Home/ Questions/Q 6930883
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:30:19+00:00 2026-05-27T11:30:19+00:00

this might be a rookie question, but how would you efficiently apply regex expressions

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this might be a rookie question, but how would you efficiently apply regex expressions on strings to retrieve parts of the string ? I have a concrete parsing to solve as an example.

If I have the string :

STRING[(val1)-{val2}-!val3!]

or

STRING[{val2}-!val3!-(val1)]

or

STRING[!val3!-(val1)-{val2}]

etc… (All 8 permutations of !val3!,(val2),{val1} that I won’t bother you with).

I can do several easy finds and splits on that to achieve my purpose, but how would you do things in a clean and safe way to get something like :

val1,val2,val3 = ... ?

UPDATE : in the string to parse, val1, val2 and val3 are variable inputs, and the three delimiters !! () {} are there to help me know where are the three values that each have another semantic meaning.

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:30:20+00:00Added an answer on May 27, 2026 at 11:30 am

    You can use lookahead assertions with capturing groups to find matches in any order:

    import re
    def matchany(subject):
        match = re.match(
            r"""
            (?=.*\(([^()]*)\))   # Find match between () --> group 1
            (?=.*\{([^{}]*)\})   # Find match between {} --> group 2
            (?=.*!([^!]*)!)      # Find match between !! --> group 3""", 
            subject, re.VERBOSE)
        return match.groups() if match else None
    

    Then you can do

    >>> matchany("STRING[(val1)-{val2}-!val3!]")
    ('val1', 'val2', 'val3')
    >>> matchany("STRING[!val3!-(val1)-{val2}]")
    ('val1', 'val2', 'val3')
    >>> matchany("STRING[(val1)-{val2}-!val3]")
    >>>
    
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