Question

This might be silly. I cannot figure it out right now.

There is a total number (x)

Which needs to be divided equally with (y)

If x is 10,000 and y is 10,

That would mean 10,000 is to be spit between 10.

How to find the starting point as

1 starts at 1 and ends 1,000
2 starts at 1,001 & ends 2,000
3 ..
4 ..
5 ..

Answer 1

This is really just some simple maths:

x = 10000
y = 10
print([(item, item+(x//y-1)) for item in range(1, x, x//y)])

Gives us:

[(1, 1000), (1001, 2000), (2001, 3000), (3001, 4000), (4001, 5000), (5001, 6000), (6001, 7000), (7001, 8000), (8001, 9000), (9001, 10000)]

Here we use the range() builtin and a list comprehension.

This works by using the range() builtin to construct a generator from 1 to below x, taking steps of x divided (integer division, so we don’t get a floating point number) by y.

We then use a list comprehension to take these values (1, 1001, 2001, ..., 9001) and then put them into tuple pairs, adding (x//y-1) (in this case 999) to the value to get the ending boundary.

Naturally, if you want to use this in a loop, for example, you would be better off with a generator expression so that it’s evaluated lazily, over a list comprehension. E.g:

>>> for number, (start, end) in enumerate((item, item+(x//y-1)) for item in range(1, x, x//y)): 
...     print(number, "starts at", start, "and ends at", end)
... 
0 starts at 1 and ends at 1000
1 starts at 1001 and ends at 2000
2 starts at 2001 and ends at 3000
3 starts at 3001 and ends at 4000
4 starts at 4001 and ends at 5000
5 starts at 5001 and ends at 6000
6 starts at 6001 and ends at 7000
7 starts at 7001 and ends at 8000
8 starts at 8001 and ends at 9000
9 starts at 9001 and ends at 10000