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Home/ Questions/Q 8688263
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T23:19:06+00:00 2026-06-12T23:19:06+00:00

This might be something too obvious. However, I couldn’t find the specific answer though

  • 0

This might be something too obvious. However, I couldn’t find the specific answer though many stackoverflow threads talk about different aspects of this.

typedef struct _tmp {
   unsigned int a;
   unsigned int b;
} tmp;

int main()
{
    int c=10;
    if (c <= sizeof tmp) {
       printf("less\n");
    } else {
       printf("more\n");
    }
    return 0;
}

I compile this prog as –

g++ -lstdc++ a.cpp

I get an error –

expected primary-expression before ‘)’ token

I think I am missing something very obvious and straightforward. But can’t seem to pinpoint it :-/

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-12T23:19:08+00:00Added an answer on June 12, 2026 at 11:19 pm

    5.3.3 Sizeof [expr.sizeof]

    1) The sizeof operator yields the number of bytes in the object representation of its operand. The operand is
    either an expression, which is an unevaluated operand (Clause 5), or a parenthesized type-id. (emphasis mine)

    In your case, it is a type-id so it must be parenthesized. What a type-id is is described in 8.1 Type names [dcl.name].

    sizeof tmp should be sizeof (tmp).

    As in

    if (c <= sizeof tmp) should be if (c <= sizeof (tmp)).

    Yup, pretty “obvious and straightforward”.

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