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Home/ Questions/Q 8750333
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T12:50:54+00:00 2026-06-13T12:50:54+00:00

This might be strange, but what I am looking for is how would I

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This might be strange, but what I am looking for is how would I make the scope of jQuery.ajaxSetup() inside a specific object only. Let me give you an example, I have two objects obj_1 and obj_2. I want to write ajaxSetup in such a way that all my ajax calls inside an object will use one set of params and all my calls in second object will use other set of params.

Eg

var obj_1 = {

    my_func : function(){

        $.ajax({
            success : function(){
                // do something
                // all ajax calls in this object should use one set of params (type,dataType,headers etc)
            }
        })

    }

};

var obj_2 = {

    my_func : function(){

        $.ajax({
            success : function(){
                // do something
                // all ajax calls in this object should use different params (type,dataType,headers etc)
            }
        })

    }

};

I want to do this so that I don’t have to write all params in every ajax call.

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  1. Editorial Team
    Editorial Team
    2026-06-13T12:50:55+00:00Added an answer on June 13, 2026 at 12:50 pm

    Your best bet is to create a function for use by the object and have it set the parameters when doing the ajax call. The object uses that function rather than calling ajax directly. E.g., a simple wrapper function.

    Alternately, you could have a standardParams property on each object that you reuse, perhaps mixing in the params that are specific to the call. Something like:

    var obj_x = {
        standardParams: {
            // These are the params that don't vary
            dataType: "json" // Or whatever
        },
    
        your_func: function() {
            $.ajax($.extend({}, this.standardParams, {
                // These are the params that vary
                success: function() { ... }
            }));
        }
    };
    

    (Note the use of jQuery.extend to mix the per-call and standard params.)

    Or of course, you could use a combination of the two (a wrapper function, which uses a standardParams property under the covers).

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