Question

This might be the question that suits to all programming languages(I guess!). I have a code like this in Groovy:

def a =['asd','sdf','sdr','asd','tty','gfdg','dfgt','rfgsf','rfas','asddre','asdfr','adsrf']
start = System.currentTimeMillis() 
println a.sort()
end = System.currentTimeMillis() 
println "Sort in-built is ${end-start}"
def InsertionSort(def b = [])
{
   for(out=1;out<b.size();out++)
    {
        temp = b[out]
        in1 = out;
        while(in1>0 && b[in1-1]>=temp)
        {
            b[in1] = b[in1-1]
            --in1
        }
        b[in1] = temp;
    }
    return b
}
start = System.currentTimeMillis() 
c = InsertionSort(a)
end = System.currentTimeMillis() 
println "Insertion Sort is ${end-start}"
println c

Clearly the above code checks the running time of in-built sort function and my function named as InsertionSort which also does the same job as sort.

Now I run this same code at different time. Say when I execute the code at time 8:34:33 pm I get the output as:

[adsrf, asd, asd, asddre, asdfr, dfgt, gfdg, rfas, rfgsf, sdf, sdr, tty]
Sort in-built is 4
Instertion sort is 6
[adsrf, asd, asd, asddre, asdfr, dfgt, gfdg, rfas, rfgsf, sdf, sdr, tty]

Now at 8:35:03 when I execute the same program I get output as:

[adsrf, asd, asd, asddre, asdfr, dfgt, gfdg, rfas, rfgsf, sdf, sdr, tty]
Sort in-built is 1
Insertion Sort is 1
[adsrf, asd, asd, asddre, asdfr, dfgt, gfdg, rfas, rfgsf, sdf, sdr, tty]

After some moment of seconds I get output as:

[adsrf, asd, asd, asddre, asdfr, dfgt, gfdg, rfas, rfgsf, sdf, sdr, tty]
Sort in-built is 0
Insertion Sort is 1
[adsrf, asd, asd, asddre, asdfr, dfgt, gfdg, rfas, rfgsf, sdf, sdr, tty]

Did you notice that the running time of method changes for each execution of the program? Noticeably, the change is vary large from first execution and second execution. So does this mean Groovy caches the latest output somewhere,for some min/sec? How come this change as per second’s?

Thanks in advance.

​

Answer 1

Many reasons.

1. Other background task taking up CPU time.
2. In languages using a JVM the JVM could have JIT enabled and optimized certain runs especially if a block of code is repeatedly run without restarting the JVM.