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This must be a stupid question, but nevertheless I find it curious:
Say I have a steady download of 128Kbps.
How much disk space is going to be consumed after a hour in Megabytes?
128 x 60 x 60 / 8 / 1024 = 56.25 MB
But
128 x 60 x 60 / 1000 /8 = 57.6 MB
So what is the correct way to calculate this?
Thanks!
Ok, I found out an official explanation from Symantec on the matter:
http://seer.entsupport.symantec.com/docs/274171.htm
It seems the idea is to convert from bits to bytes as early as possible in calculation, and then the usual 1024 division comes in place.
I just hope it’s a standard procedure, and not Symantec imposed one :).