Question

this ought to be simple, but it doesn’t seem to be working for me. i have tested it with good and bad passwords. no matter what, it will not go into the else statement. i am not sure what i am missing

my code:

$mysqli = mysqli_connect("localhost", "joeuser", "somepass", "testDB");

 if (mysqli_connect_errno()) {
      printf("Connect failed: %s\n", mysqli_connect_error());
      exit();
  } else {
      $sql = "SELECT * FROM login_info";      
      $res = mysqli_query($mysqli, $sql);

  if ($res) {
      while ($newArray = mysqli_fetch_array($res, MYSQLI_ASSOC)) {
          $id  = $newArray['first_name'];                          
          $testField = $newArray['last_name'];                      
          echo "The ID is ".$id." and the text is ".$testField."<br/>";
         }
  } else {
      printf("Could not retrieve records: %s\n", mysqli_error($mysqli));
  }

        mysqli_free_result($res);
        mysqli_close($mysqli);
  }

If i send it a user and password that do exist it does the if statement fine, but if i send it a test for one that is not in the db it still won’t do the else? why?

Answer 1

Like this:

if ($res) {
      while ($newArray = mysqli_fetch_array($res, MYSQLI_ASSOC)) {
          $id  = $newArray['first_name'];                          
          $testField = $newArray['last_name'];                      
          echo "The ID is ".$id." and the text is ".$testField."<br/>";
         }
}

if (!isset($id)) {
      printf("Could not retrieve records: %s\n", mysqli_error($mysqli));
}