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Home/ Questions/Q 4046322
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T13:32:53+00:00 2026-05-20T13:32:53+00:00

This PostgreSQL COPY command works: copy tablename from E’c:\\abc\\a.txt’; but I want the tablename

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This PostgreSQL COPY command works:

copy tablename from E'c:\\abc\\a.txt';

but I want the tablename to be dynamically generated. How can I do this?

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  1. Editorial Team
    Editorial Team
    2026-05-20T13:32:54+00:00Added an answer on May 20, 2026 at 1:32 pm

    You need to build a string, concatenating in the dynamic table name, and then use execute. Note that you escape the ‘ by ”. This also includes a dynamic name to save the file too. You need to replace savedir with the actual directory you are using.

    CREATE OR REPLACE FUNCTION dynamicCopy(tablename text, outname text) RETURNS VOID AS $$
    
    DECLARE STATEMENT TEXT;
    
    BEGIN
    
      STATEMENT := 'COPY (select * from ' || quote_ident(tablename) || ') to ''savedir' || outname ||'.txt''';
    
      EXECUTE STATEMENT;
    
    END;
    
    $$ LANGUAGE 'plpgsql';
    

    EDIT:

    Since I first wrote this, I have discovered the format function, which I think is generally easier to read than SQL generated with the concatenation operator || and more flexible.

    CREATE OR REPLACE FUNCTION dynamicCopy(tablename text, outname text) RETURNS VOID AS 
    $BODY$
    BEGIN
      EXECUTE FORMAT('COPY (SELECT * FROM %s) TO ''savedir%s.csv''',
                      tablename, 
                      outname);
    END
    $BODY$ 
    LANGUAGE plpgsql;
    

    See the official docs for a full discussion: https://www.postgresql.org/docs/current/static/plpgsql-statements.html#PLPGSQL-STATEMENTS-EXECUTING-DYN

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