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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T11:20:04+00:00 2026-05-20T11:20:04+00:00

This problem rephrases an interview question . Since this original problem seems too hard

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This problem rephrases an interview question. Since this original problem seems too hard to me I am trying to solve a simpler one: how to process an integer array to find an average of any sub-array in constant time. Obviously, we can process all sub-arrays in O(n^2). Are there better solutions?

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  1. Editorial Team
    Editorial Team
    2026-05-20T11:20:05+00:00Added an answer on May 20, 2026 at 11:20 am

    For the 1d case: compute the cumulative sums of the array, i. e. given array a, define b by

    b[0] = a[0];
    for (int i = 1; i < n; ++i)
        b[i] = b[i - 1] + a[i];
    

    To compute any average of a subarray, compute the difference of the cumultaive sum corrseponding to the end index and the one corresponding to the start index, and divide by the number of entries in the subarray. For example for the range from i+1 to j, do

    average = (b[j] - b[i]) / (double)(j - i);
    

    The same thing works in two dimensions by computing cumulative sums along the two axes.

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