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Home/ Questions/Q 7532855
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T05:34:25+00:00 2026-05-30T05:34:25+00:00

This program execution is not getting inside the if condition. please check the comment

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This program execution is not getting inside the if condition.

please check the comment i have specified.

public static void filterObject(ArrayList<treewalker.VariableNode> variableNodeslist,
            ArrayList<treewalker.ObjectNode> objectNodeslist,
            ArrayList<treewalker.ClassNode> classNodeslist) {
        int i, j;
        for (i = 0; i < variableNodeslist.size(); i++) {
            for (j = 0; j < classNodeslist.size(); j++) {
                String argu1 = variableNodeslist.get(i).typeClass.toString();
                String argu2 = classNodeslist.get(j).name.toString();
                System.out.println(argu1);
                System.out.println(argu2);
                if (argu1 == argu2)//this if loop is not getting executed 
                {
                    System.out.println("inside for");
                }
                System.out.println("hi");
            }
        }
    }
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  1. Editorial Team
    Editorial Team
    2026-05-30T05:34:26+00:00Added an answer on May 30, 2026 at 5:34 am

    Short answer:
    argu1.equals(argu2) instead of argu1 == argu2

    Longer answer:
    The == operator in Java does a reference compare.

    You want to do string comparison, use:

    if (argu1.equals(argu2))
    

    In some case the == operator might seem to do a equality check for example:

    String var1 = "abc";
    String var2 = "abc";
    
    String result = ("abc" == "abc");
    

    In this case the result is true which at first look seems to be an equality comparison but is fact a compiler optimisation where both var1 and var2 shares the same reference.

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