Question

This program works, except when the number of nJars is a multiple of 7, I will get an answer like $14.999999999999998. For 6, the output is 14.08. How do I fix exceptions for multiples of 7 so it will display something like $14.99?

import java.util.Scanner;
public class Homework_17
{
 private static int nJars, nCartons, totalOunces, OuncesTolbs, lbs;

 public static void main(String[] args)
  {
   computeShippingCost();
  }

  public static void computeShippingCost()
  {
   System.out.print("Enter a number of jars: ");
   Scanner kboard = new Scanner (System.in);
   nJars = kboard.nextInt();
   int nCartons = (nJars + 11) / 12;
   int totalOunces = (nJars * 21) + (nCartons * 25);
   int lbs = totalOunces / 16;
   double shippingCost =  ((nCartons * 1.44) + (lbs + 1) * 0.96) + 3.0;

   System.out.print("$" + shippingCost);
   }
}

Answer 1

Use a DecimalFormatter:

double number = 0.9999999999999;
DecimalFormat numberFormat = new DecimalFormat("#.00");
System.out.println(numberFormat.format(number));

Will give you “0.99”. You can add or subtract 0 on the right side to get more or less decimals.

Or use ‘#’ on the right to make the additional digits optional, as in with #.## (0.30) would drop the trailing 0 to become (0.3).