Question

this query returns the list below it, however the ids occur multiple times, can i group the ids and add up all the plays so i just get a list unique ids with the total number of plays next to it. is this possible in sql?

SELECT [fkPlayerId],[plays]
FROM [dPlaysPerDay]
INNER JOIN dWinners
ON [dPlaysPerDay].[fkPlayerId]=dWinners.[pkWinnerId]

53693   1
53695   1
53696   1
53693   1
53692   2
53698   2
53697   1
53699   2
53698   3
53693   6
53699   2
53693   2
53700   2
53698   1

Answer 1

When using GROUP BY, all data items in the SELECT, must either be included in the GROUP BY or placed in an Aggregate Function.

Therefore, fkPlayerId should be grouped by, and plays used with the SUM() function

SELECT [fkPlayerId], SUM([plays])
FROM [dPlaysPerDay]
INNER JOIN dWinners ON [dPlaysPerDay].[fkPlayerId]=dWinners.[pkWinnerId]
GROUP BY fkPlayerId

To ORDER BY the aggregate function, give the data item an alias, and Order by this:

SELECT [fkPlayerId], SUM([plays]) as TotalPlays
FROM [dPlaysPerDay]
INNER JOIN dWinners ON [dPlaysPerDay].[fkPlayerId]=dWinners.[pkWinnerId]
GROUP BY fkPlayerId
ORDER BY TotalPlays