Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6374877
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T01:32:36+00:00 2026-05-25T01:32:36+00:00

This question also has the answer , but it mentions DB2 specifically. How do

  • 0

This question also has the answer, but it mentions DB2 specifically.

How do I search for a string using LIKE that already has a percent % symbol in it? The LIKE operator uses % symbols to signify wildcards.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T01:32:37+00:00Added an answer on May 25, 2026 at 1:32 am

    Use brackets. So to look for 75%

    WHERE MyCol LIKE '%75[%]%'
    

    This is simpler than ESCAPE and common to most RDBMSes.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

This may seem an easy question, but not to me, also a search has
First of all, I know this question has already been asked but the answer
I assume that there is probably no satisfactory answer to this question, but I
I realise that this question may be almost impossible to answer definitively, but: Is
I have a bad feeling that the answer to this question is no, but
I'm pretty sure that this question already has been answered somewhere. It just seems
This question has been asked before - but with no satisfying answer at all!
I feel that this question has been asked 10^78 times, but for some reason,
I found this question , which has an answer, but facebook changed the token
I was reading over this question and wondered if the accepted answer might also

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.