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Editorial Team
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Asked: 2026-06-16T03:40:09+00:00

This question is asked and explained in JAVA PROGRAMMING LANAGUAGE book.But i m not

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This question is asked and explained in JAVA PROGRAMMING LANAGUAGE book.But i m not clear with explaination.

Can someone Explain it more clearly ?

Explaination in book is ::

This cyclic static initialization cannot be reliably detected during compilation because
the code for Y may not be written when X is compiled. If cycles happen, X’s static initializers will have been
executed only to the point where Y’s method was invoked. When Y, in turn, invokes the X method, that
method runs with the rest of the static initializers yet to be executed. Any static fields in X that haven’t had
their initializers executed will still have their default values (false, ‘/u0000’, zero, or null depending
on their type).

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1 Answer

  1. Editorial Team

    Quite simply: if a thread is already initializing a class X when it requires class X to be initialized for another reason (e.g. because class Y uses something from it) then it just skips it. All the static variables have their default values.

    For a precise description of what’s going on, see the Java Language Specification, section 12.4.2. In particular:

    If the Class object for C indicates that initialization is in progress for C by the current thread, then this must be a recursive request for initialization. Release LC and complete normally.

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