Question

This question is connected with this post of mine – Will a Single XSLT file solve this issue..or…?

Below is my XML file –

<CVs>
 <CV>
  <Name>ABC</Name>
  <Address></Address>
  <Introduction></Introduction>
  <CompSkills>Java, XSLT, XPATH, XML, Oracle, VB.NET</CompSkills>
  <Experience>
    <Profile></Profile>
    <Duration></Duration>
    <Info></Info>
  </Experience>
  <Experience>
    <Profile></Profile>
    <Duration></Duration>
    <Info></Info>
  </Experience>
  <Experience>
    <Profile></Profile>
    <Duration></Duration>
    <Info></Info>
  </Experience>
<CV>
<CV>
 <Name>XYZ</Name>
 <Address></Address>
 <Introduction></Introduction>
 <CompSkills>Java, XSLT, XPATH, XML, JSP, HTML</CompSkills>
 <Experience>
   <Profile></Profile>
   <Duration></Duration>
   <Info></Info>
 </Experience>
 <Experience>
   <Profile></Profile>
   <Duration></Duration>
   <Info></Info>
 </Experience>
 <Experience>
   <Profile></Profile>
   <Duration></Duration>
   <Info></Info>
 </Experience>

Below is my XSLT file – (well Dimitre gave this answer, but now its mine 😉 )

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:param name="pName" select="'XYZ'"/>

 <xsl:template match="node()|@*" name="identity">
   <xsl:copy>
     <xsl:apply-templates select="node()|@*"/>
   </xsl:copy>
 </xsl:template>

 <xsl:template match="CV">
   <xsl:if test="$pName = Name or $pName='*'">
     <xsl:call-template name="identity"/>
   </xsl:if>
 </xsl:template>

</xsl:stylesheet>

The above XSLT will extract matching <Name> which is passed from Java.

Now I need to know how can i modify this XSLT, so that if I pass Oracle as a parameter, then
those who have Oracle in <CompSkills> would get listed. Oracle will be one of the CompSkills..

Thanks in advance – John

Answer 1

XPath 1.0, easy way: contains function, e.g.:

<xsl:if test="contains(CompSkills, $pSkill)">