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Editorial Team
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Asked: 2026-06-18T10:53:37+00:00

This question is derive from the following question , let’s say class B extends

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This question is derive from the following question, let’s say class B extends class A

class A(object):
  def do_work(self):
    print 123

class B(A):
  def do_work(self):
    super(B,self).do_work() # versus the next statement
    super(A,self).do_work() # what's the difference?
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1 Answer

  1. Editorial Team
    super(B,self).do_work()

    will call the do_work function as seen by the parent class of B – that is, A.do_work.

    super(A,self).do_work()

    will call the do_work function as seen by the parent class of A – that is, object.do_work (which probably doesn’t exist, and thus would likely raise an exception).

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