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Home/ Questions/Q 8170509
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T21:08:54+00:00 2026-06-06T21:08:54+00:00

This question is probably a combination of following two questions, but with slightly different

  • 0

This question is probably a combination of following two questions, but with slightly different perspective.

Yielding sub combinations

Yield sub combinations with limit

I adapted the code in first question for my requirement.

def sub_combinations(segment):
    for i in range(1, len(segment)):
            for j in sub_combinations(segment[i:]):
                    yield [segment[:i]] + j 
    yield [segment]

max = 4

for p in sub_combinations([1, 2, 3, 4, 5, 6, 7]):
    if len(p) == max:
        print map(list, p)

This gives output as:

[[1], [2], [3], [4, 5, 6, 7]]
[[1], [2], [3, 4], [5, 6, 7]]
[[1], [2], [3, 4, 5], [6, 7]]
[[1], [2], [3, 4, 5, 6], [7]]
[[1], [2, 3], [4], [5, 6, 7]]
[[1], [2, 3], [4, 5], [6, 7]]
[[1], [2, 3], [4, 5, 6], [7]]
[[1], [2, 3, 4], [5], [6, 7]]
[[1], [2, 3, 4], [5, 6], [7]]
[[1], [2, 3, 4, 5], [6], [7]]
[[1, 2], [3], [4], [5, 6, 7]]
[[1, 2], [3], [4, 5], [6, 7]]
[[1, 2], [3], [4, 5, 6], [7]]
[[1, 2], [3, 4], [5], [6, 7]]
[[1, 2], [3, 4], [5, 6], [7]]
[[1, 2], [3, 4, 5], [6], [7]]
[[1, 2, 3], [4], [5], [6, 7]]
[[1, 2, 3], [4], [5, 6], [7]]
[[1, 2, 3], [4, 5], [6], [7]]
[[1, 2, 3, 4], [5], [6], [7]]

Now the problem is, this takes too much time for larger sized lists. Is there more efficient/pythonic way of implementing this? How could I incorporate argument ‘max’ in the function itself? I tried a lot of ways, but having hard time working with recursive functions.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T21:08:57+00:00Added an answer on June 6, 2026 at 9:08 pm

    It seems your desired result can be described as all the ways to split a list in (say) 4 non-empty sublists. This can be done by generating all possible combinations of split positions:

    def split_sequence(seq, chunks):
        for splits in itertools.combinations(range(1, len(seq)), chunks - 1):
            left = (None,) + splits
            right = splits + (None,)
            yield [seq[l:r] for l, r in zip(left, right)]
    

    Example output:

    >>> list(split_sequence(range(7), 4))
    [[[0], [1], [2], [3, 4, 5, 6]],
     [[0], [1], [2, 3], [4, 5, 6]],
     [[0], [1], [2, 3, 4], [5, 6]],
     [[0], [1], [2, 3, 4, 5], [6]],
     [[0], [1, 2], [3], [4, 5, 6]],
     [[0], [1, 2], [3, 4], [5, 6]],
     [[0], [1, 2], [3, 4, 5], [6]],
     [[0], [1, 2, 3], [4], [5, 6]],
     [[0], [1, 2, 3], [4, 5], [6]],
     [[0], [1, 2, 3, 4], [5], [6]],
     [[0, 1], [2], [3], [4, 5, 6]],
     [[0, 1], [2], [3, 4], [5, 6]],
     [[0, 1], [2], [3, 4, 5], [6]],
     [[0, 1], [2, 3], [4], [5, 6]],
     [[0, 1], [2, 3], [4, 5], [6]],
     [[0, 1], [2, 3, 4], [5], [6]],
     [[0, 1, 2], [3], [4], [5, 6]],
     [[0, 1, 2], [3], [4, 5], [6]],
     [[0, 1, 2], [3, 4], [5], [6]],
     [[0, 1, 2, 3], [4], [5], [6]]]
    
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