Question

this question is regarding the syntax of an array of array of structs.

I have a struct that takes in two ints:

struct point
{
    int x, y;
};

I have created another struct that takes in 8 of these structs:

//Creating an Array of Array of structs
struct Arraypoint
{
    point variable[8];
};
//Not sure if this is the correct way to do it.

Now, in main, I want to declare an array variable of type Arraypoint with 8 indices, so effectively I will have 8 * 8 = 64 elements of struct point and 128 ints (64 x and 64 y).

Also, how would I access an individual element struct point from the array Arraypoint?

Okay after having declared in main lets say Arraypoint is 2.

Arraypoint arr[2];

How do I initialize the elements without having to type in arr[0].variable[0].x = ... or without using for loops.
Why can’t I do the following, it doesn’t seem to work.

Arraypoint arr[2] = {  {(x,y),(x,y),(x,y),(x,y),(x,y),(x,y),(x,y),(x,y)},
                       {(x,y),(x,y),(x,y),(x,y),(x,y),(x,y),(x,y),(x,y)}  }//xy are rand

I have used curly braces in my code, the error returned is missing braces around initializer for type point and too many initializers for type Arraypoint.

Answer 1

got it: ideone.com/ix3hC. Arraypoint::variable has to have it’s own { } pair.

struct point
{
    int x, y;
};
#define P {0, 0}

struct Arraypoint
{
    point variable[8];
};
#define V { P, P, P, P, P, P, P, P} 
#define AP { V }  //this is the pair you missed

int main() {
    Arraypoint arr[2] = { AP, AP };
}