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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T05:08:37+00:00 2026-06-06T05:08:37+00:00

This question is related to awk, I suppose. I have no experience with awk.

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This question is related to awk, I suppose.
I have no experience with awk. I tried lots of things but I could not find any solution.

Actually, I want to read a file line by line, then replace the whole line with perl.

I simplified the code. I hope you can understand.

new_line1=1234567
new_line2=1234/567

perl -pi -e "s/$new_line1/$new_line2/g" $FILE

The problem is that when I use is related to /.

Number found where operator expected at -e line 1, near "s/1234567/1234/567"
syntax error at -e line 1, near "s/1234567/1234/567"

Because bash assumes that perl -pi -e "s/1234567/1234**/**567/g" $FILE

How can I avoid it.

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  1. Editorial Team
    Editorial Team
    2026-06-06T05:08:38+00:00Added an answer on June 6, 2026 at 5:08 am

    Use a different delimiter from / if you don’t want to escape it:

    perl -pi -e "s#$new_line1#$new_line2#g" $FILE
    
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