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Home/ Questions/Q 9054655
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T13:44:38+00:00 2026-06-16T13:44:38+00:00

This question is related to my previous question, Creating a Rails partial that is

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This question is related to my previous question, Creating a Rails partial that is model-agnostic.

I am trying to create a Rails partial that is given a variable, say, seasonal_type, and does several different operations, such as querying a resource, and accessing instance variables, based on the value of the variable.

To be more concrete: I have the two models SafetyTest and TeamDue, which belong to Student. In one particular case in this partial, I need to call either
@student.safety_tests or @student.team_dues. I would like to pass the variable seasonal_type to the partial and like that determine which of the two is executed. How would I be able to do this? The value of the variable could be whatever is most convenient, such as a symbol (:safety_test) or a model (SafetyTest).

There is also another part to this question. In my controller, I precaculcated some instance variables for SafetyTest and TeamDue, such as @valid_safety_test and @valid_team_due. In my partial, how can I use either of these two instance variables, based on the value of seasonal_type? Or should I just calculate these values inside the partial, even though that would be against the MVC structure?

Any help would be much appreciated.

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  1. Editorial Team
    Editorial Team
    2026-06-16T13:44:39+00:00Added an answer on June 16, 2026 at 1:44 pm

    Here is the answer:

    In my controller, I created an array with the models of both seasonal types: [SafetyTest, TeamDue]

    Then I iterated over this array, and used the model to query all the information that I needed from the database. I put that information into an array and passed it on to the view with an instance variable. So this array also has two items, one for SafetyTest and one for TeamDue.

    Then the partial iterates through this array and renders the view necessary.

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