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Home/ Questions/Q 9196453
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T21:51:11+00:00 2026-06-17T21:51:11+00:00

This recursive function: myGrid = [[0,0,0], [0,0,0], [0,0,0]] def testchange(grid, number=-1, number2=0): kgrid =

  • 0

This recursive function:

myGrid = [[0,0,0],
          [0,0,0],
          [0,0,0]]

def testchange(grid, number=-1, number2=0):
    kgrid = list(grid)
    kgrid[number][number2] = 2
    number += 1
    number2 += 1
    if number < 2:
        print '1', kgrid
        testchange(kgrid,number,number2)
        print '2', kgrid
        testchange(kgrid,number+1,number2)

testchange(myGrid);

prints out:

1 [[0, 0, 0], [0, 0, 0], [2, 0, 0]]
1 [[0, 2, 0], [0, 0, 0], [2, 0, 0]]
2 [[0, 2, 0], [0, 0, 2], [2, 0, 0]]
2 [[0, 2, 0], [0, 0, 2], [2, 0, 2]]

in my function after I first call testchange() kgrid should not be changed, but as you can see it is, why?

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  1. Editorial Team
    Editorial Team
    2026-06-17T21:51:12+00:00Added an answer on June 17, 2026 at 9:51 pm

    To copy grid, use copy.deepcopy(). Otherwise a shallow copy is made, leading to the behaviour you describe.

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