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Home/ Questions/Q 8590325
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T23:16:09+00:00 2026-06-11T23:16:09+00:00

This Ruby code: income = 100 bills = 52 puts income – bills threw

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This Ruby code:

income = "100"
bills  = "52"

puts income - bills

threw an error:

./to_f.rb:6: undefined method `-' for "100":String (NoMethodError)

Does Ruby not auto-convert strings to numbers when performing math operations on them?

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  1. Editorial Team
    Editorial Team
    2026-06-11T23:16:10+00:00Added an answer on June 11, 2026 at 11:16 pm

    Ruby is a dynamically-typed, strictly-typed (or “strongly-typed”) language. Lua is another such language. The former means that variables can hold any class of value. The latter—what you are running into—means that type coercion does not happen automatically.

    Contrast these with JavaScript, which is dynamically-typed and loosely-typed. In JavaScript you can write var x = [] + false; and it will attempt to do something helpful. For another example, in JavaScript "1" + 1 == "11" but "1" - 1 == 0. Ruby will not do any such thing.

    In your case you need:

    puts income.to_i - bills.to_i
    

    Note that—because most operators are implemented as methods in Ruby—each class can choose how the operator handles operands of various types. For example:

    class Person
      def +( something )
        if something.is_a?(Numeric)
          self.weight += something
        elsif something.is_a?(Time)
          self.age += something
        else
          raise "I don't know how to add a #{something.class} to a Person."
        end
      end
    end
    

    Most of the time the core libraries do not attempt to be so clever, however.

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