Question

This script is supposed to get the content of a text area and submit it to mysql, but it isnt can anyone see why?

    if ($_SERVER["REQUEST_METHOD"] == "POST") 
{
$error = '';
$like = mysql_real_escape_string($_POST['like_box']);

mysql_query("INSERT INTO likes (like) VALUES ($like)");

$id = mysql_query("SELECT id FROM likes WHERE like=$like");
header('Location:like.php?id='.$id.'');
}?>



<form method="post" action="post.php">
                <textarea name="like_box" id="like_box" style="border-style: none; border-color: inherit; border-width: 0; width: 458px; height: 65px" class="style11120"></textarea>

            <tr>
                <td style="height: 53px">
                <div class="style11116" style="width: 417px">
                    <input name="Submit" type="submit" value="submit" />
                    </form>

Answer 1

Having some error reporting would tell you that you need ‘ around the $like and you need ` around like in the columns section, since like is a reserved word, inside the insert.

mysql_query("INSERT INTO likes (`like`) VALUES ('$like')") or trigger_error('Query Error: ' . mysql_error());

Should work.

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Also you will need to enclose the like in ` for the select:

$id = mysql_query("SELECT id FROM likes WHERE `like`=$like") or trigger_error('Query Failed: ' . mysql_error());