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Editorial Team
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Asked: 2026-05-13T05:53:27+00:00

This seems like a common task, alter some elements of an array, but my

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This seems like a common task, alter some elements of an array, but my solution didn’t feel very pythonic. Is there a better way to build urls with list comprehension?

links = re.findall(r"(?:https?://|www\.|https?://www\.)[\S]+", text)
if len(links) == 0:
    return text
urls = []
for link in links:
    if link[0:4] == "www.":
        link = "http://" + link
    urls.append(link)

Maybe something like

links = re.findall(r"(?:https?://|www\.|https?://www\.)[\S]+", text)
if len(links) == 0:
    return text
urls = map(lambda x : something(x), links)
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1 Answer

  1. Editorial Team
    ["http://"+link if link[0:4]=='www.' else link for link in links]

    or 

    [link[0:4]=='www.' and "http://"+link or link for link in links]

    Notes:
    ("http://"+link if link[0:4]=='www.' else link) – this is ternary operator like ?: in C

    (link[0:4]=='www.' and "http://"+link or link) – this has the same meaning.

    On another subject: I would test for http://, not for www. Domains don’t have to start with www. For instance, http://stackoverflow.com.

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