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Editorial Team
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Editorial Team
Asked: June 19, 20262026-06-19T00:08:01+00:00 2026-06-19T00:08:01+00:00

This seems like a simple question but I have been unable to find an

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This seems like a simple question but I have been unable to find an answer anywhere. If I have a Matlab matrix A consisting of an arbitrary number of rows, how would I filter these rows based on the value of some function f (the argument of which is a row vector)? In other words, how would I keep only the rows of matrix A for which f is true? I tried

A(f(A(:)), :)

but to no success. Any help would be greatly appreciated.

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  1. Editorial Team
    Editorial Team
    2026-06-19T00:08:02+00:00Added an answer on June 19, 2026 at 12:08 am

    As Dan answered, you can filter the rows of a matrix according to a logical vector. Let selectRows be a logical vector with numel(selectRows) == size(A,1) with true for rows to be kept, and false for rows to be discarded. Then:

    A( ~selectRows, : ) = [];
    

    Will remove all rows for which selectRows == false.

    Now, the question is how to generate the logical vector selectRows using the function f?

    If f knows how to process multiple rows, and return multiple true/false values accordingly, then

    selectRows = f(A);
    

    Should do the trick.

    However, if f only knows how to process one row at a time you will need to loop through the rows. One way of doing so would be

    selectRows = cellfun( @f, mat2cell( A, ones(size(A,1)), size(A,2) ) );
    
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