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Home/ Questions/Q 8437257
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T07:22:55+00:00 2026-06-10T07:22:55+00:00

This seems pretty simple, but I can’t figure it out. I’m new to javascript/

  • 0

This seems pretty simple, but I can’t figure it out. I’m new to javascript/ jquery.

i want to trigger a function to move a div onmouseover, and another onmouseout. I want to call this same function on several different divs. how would I do this without writing multiple functions?

  <div id="indexJoinBanner" onmouseover="moveDivRight()" onmouseout="moveDivLeft()"> 
  <!-- end #indexJoinBanner --></div>
  <div id="indexJoinBanner2" onmouseover="moveDivRight()" onmouseout="moveDivLeft()"> 
  <!-- end #indexJoinBanner2 --></div>



function moveDivRight(){
  $("#indexJoinBanner").animate({
    left: "0px",
  },500 );
};

function moveDivLeft() {
  $("#indexJoinBanner").animate({
    left: "-150px",
  },500 );
}

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T07:22:56+00:00Added an answer on June 10, 2026 at 7:22 am

    You can pass the div to the function like

    <div id="indexJoinBanner" onmouseover="moveDivRight(this)" onmouseout="moveDivLeft(this)"> 
    

    and use it in the function

    function moveDivRight(div){
      $(div).animate({
        left: "0px",
      },500 );
    };
    
    function moveDivLeft(div) {
      $(div).animate({
        left: "-150px",
      },500 );
    }
    

    this in the attributes specify the current element.

    Alternatively you can attach handler using .on() instead of onmouseover and onmouseout attributes, give all the elements you want to attach the handler a class then

    $('.someclass').on('mouseover', function () {
      $(this).animate({
        left: "0px",
      },500 );
    }).on('mouseout', function () {
      $(this).animate({
        left: "-150px",
      },500 );
    })
    

    DEMO

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