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Home/ Questions/Q 917417
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T18:12:29+00:00 2026-05-15T18:12:29+00:00

This seems really simple but it is giving me a hard time figuring it

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This seems really simple but it is giving me a hard time figuring it out as I’m new to perl.. I’ve been looking through a lot of documentation now about loops and I am still stumped by this… I have a sub that contains a while loop and I want to use a variable value from within the loop outside of the loop (after the loop has run), however when I try to print out the variable, or return it out of the sub, it doesn’t work, only when I print the variable from within the loop does it work.. I would appreciate any advice as to what I’m doing wrong.

Doesn’t work (doesn’t print $test ):

sub testthis {    
    $i = 1;
    while ($i <= 2) {    
        my $test = 'its working' ;    
        $i++ ;
    }
    print $test ;
}

&testthis ;

Works, prints $test:

sub testthis {
    $i = 1;
    while ($i <= 2) {
        my $test = 'its working' ;
        $i++ ;
        print $test ;
    }
}

&testthis ;
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  1. Editorial Team
    Editorial Team
    2026-05-15T18:12:30+00:00Added an answer on May 15, 2026 at 6:12 pm

    You declare variable test inside the loop, so it scope is the loop, as soon as you leave the loop the variable is not longer declared.
    Add my $test; just between $i=1 and while(..) and it will work. The scope will now be the entire sub instead of only the loop

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