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Home/ Questions/Q 921923
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T18:56:41+00:00 2026-05-15T18:56:41+00:00

This seems simple, but it is impossible to search the web for… I have

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This seems simple, but it is impossible to search the web for…

I have a legacy application that uses JDBC directly with no frameworks, and I’m having to add some new features. I’m having issues finding out how to use the IN() function via JDBC.

I would like to have a query like the following

SELECT * from animals WHERE animal_name IN (...)

Where the … is an array of values.
Using JDBC i would think I would do the following.

PreparedStatement st = conn.prepareStatement("SELECT * from animals WHERE animal_name IN (?);");
st.setArray(arrayVals);
ResultSet rs = st.executeQuery();
....

But this does not work, and I’m finding it next to impossible to find any reference to this on the web.

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  1. Editorial Team
    Editorial Team
    2026-05-15T18:56:42+00:00Added an answer on May 15, 2026 at 6:56 pm

    Replace your code with something like:

    StringBuilder sb = new StringBuilder("SELECT * from animals WHERE animal_name IN (");
    // 1. assemble query parameters
    for (int i = 0; i < arrayVals.size(); i++) {
        sb.append("?");
        if (i + 1 < arrayVals.size()) sb.append(",");
    }
    sb.append(")");
    // 2. add the variables
    PreparedStatement st = conn.prepareStatement(sb.toString());
    for (int i = 0; i < arrayVals.size(); i++) {
        // May need to replace setter depending on type of object
        st.setObject(i + 1, o);
    }
    

    As an alternative, using spring JDBCs JdbcTemplate you would replace part 2 with this:

    jdbcTemplate.query(sb.toString(), arrayVals.toArray(), animalRowMapper);
    

    JdbcTemplate will determine the sql types needed for each parameter.

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