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Home/ Questions/Q 6032675
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T05:22:09+00:00 2026-05-23T05:22:09+00:00

This seems so simple, but for some reason I’m confusing myself. The thing line

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This seems so simple, but for some reason I’m confusing myself. The “thing” line is giving me the error.
The parsing functions are correct (stolen from RWH). I just have a type error.

Thanks!

import Text.ParserCombinators.Parsec
import System.IO

main = do 
   csv_cont <- openFile "aCSV.txt" ReadMode
   csv_cont1 <- hGetContents csv_cont
   thing <- parseCSV csv_cont1
   return () 


csvFile = endBy line eol
line = sepBy cell (char ',')
cell = many (noneOf ",\n")
eol = char '\n'

parseCSV :: String -> Either ParseError [[String]]
parseCSV input = parse csvFile "(unknown)" input
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T05:22:09+00:00Added an answer on May 23, 2026 at 5:22 am

    parseCSV is a pure function (note, no IO in the type). So you don’t use “do notation” to bind its result. Instead, just regular let is appropriate:

    import Text.ParserCombinators.Parsec
    import System.IO
    
    main = do
       h <- openFile "aCSV.txt" ReadMode
       s <- hGetContents h
       let thing = parseCSV s
       print thing
    
    
    csvFile = endBy line eol
    line    = sepBy cell (char ',')
    cell    = many (noneOf ",\n")
    eol     = char '\n'
    
    parseCSV :: String -> Either ParseError [[String]]
    parseCSV s = parse csvFile "(unknown)" s
    

    Here, with more idiomatic naming and identation.

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