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Asked: May 10, 20262026-05-10T22:58:02+00:00 2026-05-10T22:58:02+00:00

This seems to me to be the kind of issue that would crop up

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This seems to me to be the kind of issue that would crop up all the time with SQL/database development, but then I’m new to all this, so forgive my ignorance.

I have 2 tables:

CREATE TABLE [dbo].[Tracks](     [TrackStringId] [bigint] NOT NULL,     [Id] [bigint] IDENTITY(1,1) NOT NULL,     [Time] [datetime] NOT NULL,  CONSTRAINT [PK_Tracks] PRIMARY KEY CLUSTERED  (     [Id] ASC ) WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF,         IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON,         ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY] ) ON [PRIMARY]  GO  ALTER TABLE [dbo].[Tracks] CHECK CONSTRAINT [FK_Tracks_AudioStreams] GO  ALTER TABLE [dbo].[Tracks]  WITH CHECK ADD  CONSTRAINT [FK_Tracks_TrackStrings]     FOREIGN KEY([TrackStringId]) REFERENCES [dbo].[TrackStrings] ([Id]) GO  ALTER TABLE [dbo].[Tracks] CHECK CONSTRAINT [FK_Tracks_TrackStrings] GO 

and

CREATE TABLE [dbo].[TrackStrings](     [Id] [bigint] IDENTITY(1,1) NOT NULL,     [String] [nvarchar](512) NOT NULL,  CONSTRAINT [PK_Strings] PRIMARY KEY CLUSTERED  (     [Id] ASC ) WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF,         IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON,         ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY] ) ON [PRIMARY] 

I want to insert a new entry into the tracks table. This will also involve inserting a new entry in the trackstrings table, and ensuring that the foreign key column trackstringid in tracks points to the new entry in trackstrings. What is the most efficient means of achieving this?

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  1. 2026-05-10T22:58:02+00:00Added an answer on May 10, 2026 at 10:58 pm

    First, insert into TrackStrings, omitting the primary key column from the column list. This invokes its IDENTITY column which generates a value automatically.

    INSERT INTO [dbo].[TrackStrings] ([String])    VALUES ('some string'); 

    Second, insert into Tracks and specify as its TrackStringId the function SCOPE_IDENTITY(), which returns the most recent value generated by an IDENTITY column in your current scope.

    INSERT INTO [dbo].[Tracks] ([TrackStringId], [Time])    VALUES (SCOPE_IDENTITY(), CURRENT_TIMESTAMP()); 
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