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Home/ Questions/Q 8616457
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T05:37:28+00:00 2026-06-12T05:37:28+00:00

This should be a super simple thing, but I am having an issue working

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This should be a super simple thing, but I am having an issue working this out. I am trying to implement a sort to move all of one type of objects to the top of a list. For example, a list of tasks, I would like to sort it so all the tasks of a particular owner appear at the top of the list. This is what I have now:

    this.sortByOwner = function(owner) {
        return tasks.sort(function(a, b) {

            var nameA = a.ownerUser.displayName.toLowerCase();     
            var nameB = b.ownerUser.displayName.toLowerCase();

            var displayName = owner.displayName.toLowerCase();

             if (nameA == displayName) //sort string descending
                 return -1; 
             else if (nameA == "")
                 return 1;
             return 0; //default return value (no sorting)
        });
    };

but this doesn’t work quite right. They do appear to be grouping the tasks, but unfortunately, the users tasks are not appearing at the top. What I would expect to see is the tasks that are owned by the specific person would appear at the top. What am I doing wrong here?

Including a basic JSFiddle example: http://jsfiddle.net/zJwUn/5/

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  1. Editorial Team
    Editorial Team
    2026-06-12T05:37:29+00:00Added an answer on June 12, 2026 at 5:37 am

    You didn’t handle the case where nameB is the displayName. This works for me:

    function sortByOwner(owner) {
        return tasks.sort(function(a, b){
            var nameA=a.displayName.toLowerCase(), nameB=b.displayName.toLowerCase();
            var displayName = owner.displayName.toLowerCase();
            if (nameA == displayName) //sort string descending
                return -1;
            if (nameA == "")
                return 1;
            if (nameB == displayName) //sort string descending
                return 1;
            if (nameB == "")
                return -1;
            return 0; //default return value (no sorting)
        })
    }
    
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