Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7651515
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T11:31:36+00:00 2026-05-31T11:31:36+00:00

This should be easy. I think I must be getting caught up on naming.

  • 0

This should be easy. I think I must be getting caught up on naming.

Both a ‘manager’ and a ‘subordinate’ (employee) are of class “Person”.

Here’s what I have:

class Person < ActiveRecord::Base
  has_many :person_manager_assignments
  has_many :managers, :through => :person_manager_assignments
  has_many :subordinates, :through => :person_manager_assignments
end

class PersonManagerAssignment < ActiveRecord::Base
  has_one :subordinate, :class_name => "Person", :foreign_key => "id", :primary_key => 'person_id'
  has_one :manager, :class_name => "Person", :foreign_key => "id", :primary_key => 'manager_id'
end

Which works great for checking and assigning managers.

I’m caught on the part about subordinates. It returns the Person’s self, instead of their subordinates:

p.subordinates
  Person Load (0.5ms)  SELECT "people".* FROM "people" INNER JOIN "person_manager_assignments" ON "people"."id" = "person_manager_assignments"."person_id" WHERE "person_manager_assignments"."person_id" = 15973

See the bit where in the WHERE clause where it’s matching “person_id”? I need that to be “manager_id”, but messing with the PersonManagerAssignment associations foreign_key and primary_key values doesn’t seem to help.

Any ideas?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-31T11:31:38+00:00Added an answer on May 31, 2026 at 11:31 am

    Answer is essentially here: http://railscasts.com/episodes/163-self-referential-association

    So I think you need this:

    class Person < ActiveRecord::Base
      has_many :person_manager_assignments
      has_many :managers, :through => :person_manager_assignments
      has_many :subordinate_relationships, :class_name=>"PersonManagerAssignment", :foreign_key=>"manager_id"
      has_many :subordinates, :through => :subordinate_relationships, :source=>:person
    end
    

    and

    class PersonManagerAssignment < ActiveRecord::Base
      belongs_to :person
      belongs_to :manager, :class_name=>"Person"
    end
    

    Rock on.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I think this should be easy, but it's evading me. I've got a many-to-many
think this should be an easy one... I want to get the currently selected
This seems like it should be easy yet I must be missing something. I
This seems like it should be an easy thing to do, but for the
This should be easy for many of you, but for me it's just another
This should be easy, but I'm not sure how to best go about it.
This should be easy, just curious. I know httpd is the HTTP daemon, just
This should be easy (at least no one else seems to be having a
OK, I'm feeling like this should be easy but am obviously missing something fundamental
This should be an easy one. I have a table like so: <table> <tr>

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.