Question

This should be the right code but its not working

<input type="radio" name="test">1
<input type="radio" name="test">2

$('input[name=test]').click(function() { 
    $('input[name=test]').attr(‘checked’,false);
});

example here

http://jsfiddle.net/8jKJc/16/

EDIT:

I forgot the line that should say if its checked then uncheck it

Answer 1

Change .attr to .prop and it will work fine. You will also need to change the quotes you are using around “checked” to be the right type, as that is also causing it to break at the moment:

$('input[name=test]').click(function() { 
    $(this).prop('checked',false);
});

You can see this working in this example fiddle.

Update (based on comment)

Now that I actually understand what is required, a different approach is needed. You need to remember the previous value of the checked property, by storing it in an attribute:

$('input[name=test]').click(function(e) { 
    var previous = $(this).attr('previous');
    if(previous){
        $(this).prop('checked', false)
    }
    $(this).attr('previous', $(this).prop('checked'));
});

See this working here.

Update 2 (based on further comments)

The above code from the first update does not quite work, because when clicking a different radio button in the set, the previous attribute of the previously checked radio remains set, but the radio is not actually checked. We can avoid this as follows:

var previousElem;
$('input[name=test]').click(function(e) { 
    var previous = $(this).attr('previous');
    if(previous && previousElem === this){
        $(this).prop('checked', false);
    }
    previousElem = this;
    $(this).attr('previous', $(this).prop('checked'));
});