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Home/ Questions/Q 8632497
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T09:21:41+00:00 2026-06-12T09:21:41+00:00

This simple code that simply tries to replace semicolons (at i-specified postions) by colons

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This simple code that simply tries to replace semicolons (at i-specified postions) by colons does not work:

for i in range(0,len(line)):
     if (line[i]==";" and i in rightindexarray):
         line[i]=":"

It gives the error

line[i]=":"
TypeError: 'str' object does not support item assignment

How can I work around this to replace the semicolons by colons? Using replace does not work as that function takes no index- there might be some semicolons I do not want to replace.

Example

In the string I might have any number of semicolons, eg “Hei der! ; Hello there ;!;”

I know which ones I want to replace (I have their index in the string). Using replace does not work as I’m not able to use an index with it.

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  1. Editorial Team
    Editorial Team
    2026-06-12T09:21:42+00:00Added an answer on June 12, 2026 at 9:21 am

    Strings in python are immutable, so you cannot treat them as a list and assign to indices.

    Use .replace() instead:

    line = line.replace(';', ':')
    

    If you need to replace only certain semicolons, you’ll need to be more specific. You could use slicing to isolate the section of the string to replace in:

    line = line[:10].replace(';', ':') + line[10:]
    

    That’ll replace all semi-colons in the first 10 characters of the string.

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