Question

This string operation prints out a double in short-hand, and I can’t work out why. Why is this happening, and how can I get the full output like the first line of output?

string myString = "The value is ";
ss.str(""); // stringstream from ealier
ss.clear();
ss << myDouble; // Double with value 0.000014577
myString.append(ss.str());
cout << myDouble << endl;
cout << myString << endl;

$ ./myapp
0.000014577
The value is 1.4577e-05

Answer 1

its default behaviour you should use precision to use fixed precision

#include <string>
#include <iostream>
#include <iomanip>

using namespace std;

int main() {
double v = 0.000014577;
cout << fixed << v << endl;
}