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Home/ Questions/Q 714885
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T05:07:30+00:00 2026-05-14T05:07:30+00:00

This table is used to store sessions (events): CREATE TABLE session ( id int(11)

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This table is used to store sessions (events):

CREATE TABLE session (
  id int(11) NOT NULL AUTO_INCREMENT
, start_date date
, end_date date
);

INSERT INTO session
  (start_date, end_date)
VALUES
  ("2010-01-01", "2010-01-10")
, ("2010-01-20", "2010-01-30")
, ("2010-02-01", "2010-02-15")
;

We don’t want to have conflict between ranges.
Let’s say we need to insert a new session from 2010-01-05 to 2010-01-25.
We would like to know the conflicting session(s).

Here is my query:

SELECT *
FROM session
WHERE "2010-01-05" BETWEEN start_date AND end_date
   OR "2010-01-25" BETWEEN start_date AND end_date
   OR "2010-01-05" >= start_date AND "2010-01-25" <= end_date
;

Here is the result:

+----+------------+------------+
| id | start_date | end_date   |
+----+------------+------------+
|  1 | 2010-01-01 | 2010-01-10 |
|  2 | 2010-01-20 | 2010-01-30 |
+----+------------+------------+

Is there a better way to get that?


fiddle

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T05:07:30+00:00Added an answer on May 14, 2026 at 5:07 am

    I had such a query with a calendar application I once wrote. I think I used something like this:

    ... WHERE new_start < existing_end
          AND new_end   > existing_start;
    

    UPDATE This should definitely work ((ns, ne, es, ee) = (new_start, new_end, existing_start, existing_end)):

    1. ns – ne – es – ee: doesn’t overlap and doesn’t match (because ne < es)
    2. ns – es – ne – ee: overlaps and matches
    3. es – ns – ee – ne: overlaps and matches
    4. es – ee – ns – ne: doesn’t overlap and doesn’t match (because ns > ee)
    5. es – ns – ne – ee: overlaps and matches
    6. ns – es – ee – ne: overlaps and matches

    Here is a fiddle

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