Question

this way i am sending my json data

this way i construct my json data like below one

---

function Post(carousel, first, last, per_page, page) {
  var json = "{'Name':'" + $("input[id*='txtName']").val() +
            "','Subject':'" + $("input[id*='txtSubject']").val() +
            "','Email':'" + $("input[id*='txtEmail']").val() +
            "','Message':'" + jQuery.trim($('.message').val()) + "'}";



    $.ajax({
        type: "POST",
        url: "Feedback.aspx/SaveData",
        data: json ,
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        success: function (data) {
           'here is my success code'
        }
    });
}

so i just want to know how to write the code in the server side with c# which will deserialize my json data to a feedback class.

my feedback class has same property like name,subject,email,message etc. so tell me how to fill the feedback class with deserialization.

please help me with code. thanks

Answer 1

You actually don’t need to do anything. ASP.NET will do it for you. Just define your method with the appropriate parameters, and it will work automagically:

[WebMethod]
public static void SaveData(string Name, string Subject, string Email, string Message)
{
    // Do something
}

Or since you already have this class defined, you just need to wrap your javascript fields around an object:

var json = "{'msg':{'Name':'" + $("input[id*='txtName']").val() +
            "','Subject':'" + $("input[id*='txtSubject']").val() +
            "','Email':'" + $("input[id*='txtEmail']").val() +
            "','Message':'" + jQuery.trim($('.message').val()) + "'}}";

[WebMethod]
public static void SaveData(Feedback msg)
{
    // Do something
}