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Home/ Questions/Q 570961
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T13:27:25+00:00 2026-05-13T13:27:25+00:00

This weekend I spend a few minutes thrashing together an algorithm that would take

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This weekend I spend a few minutes thrashing together an algorithm that would take in a heading (in degrees) and return a String for the cardinal direction (I’m using it in an android compass application I’m using). What I ended up with was this:

private String headingToString(Float heading)
{
    String strHeading = "?";
    Hashtable<String, Float> cardinal = new Hashtable<String, Float>();
    cardinal.put("North_1", new Float(0));
    cardinal.put("Northeast", new Float(45));
    cardinal.put("East", new Float(90));
    cardinal.put("Southeast", new Float(135));
    cardinal.put("South", new Float(180));
    cardinal.put("Southwest", new Float(225));
    cardinal.put("West", new Float(270));
    cardinal.put("Northwest", new Float(315));
    cardinal.put("North_2", new Float(360));

    for (String key: cardinal.keySet())
    {
        Float value = cardinal.get(key);
        if (Math.abs(heading - value) < 30)
        {
            strHeading = key;
            if (key.contains("North_"))
            {
                strHeading = "North";
            }
            break;
        }
    }
    return strHeading;
}

My question is, is this the best way of doing this? It must have been done many times before although I haven’t done a search for examples on the web yet. Have any other people tried this and found a neater solution?

Edit for The Reverand’s Thilo’s, shinjin’s and Chrstoffer’s responses:

The Solution

public static String headingToString2(double x)
{
    String directions[] = {"N", "NE", "E", "SE", "S", "SW", "W", "NW", "N"};
    return directions[ (int)Math.round((  ((double)x % 360) / 45)) ];
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T13:27:25+00:00Added an answer on May 13, 2026 at 1:27 pm

    That’s fine in most cases, though to make it optimized and (IMO) cleaner, what you could do is find a function to relate the input heading to one used in the map.

    For example:
    (I’m pretty sure this is right, but you’ll want to check it)

    45* (int)Math.round((  ((double)x % 360) / 45))
    

    What this does is first x % 360 makes sure the heading is within a valid range. then

    45 * round(.../45)
    

    finds the closest multiple of 45.

    Now change your map to be

      HashMap<Integer, String> map = new HashMap<Integer, String>()
      map.put(0, "North")
      map.put(45, "Northeast")
      etc...
    

    So, now your algorithm becomes a fast mathemtical calculation rather than iterating through the map. Furthermore, you don’t need as Hashtable here since it provides constructs for concurrency (if I remember correctly) and in your case it would actually cause a performance decrease.

    Once again, the performance hit may be completely negligible for your needs.

    Edit for Thilo’s and shinjin’s suggestions:

    Instead of multiplying by 45, just keep the rest of the equation, which gives you values for 0-7, and make an array of your strings.

    String directions[] = {"N", "NE", "E", "SE", "S", "SW", "W", "NW"}
    return directions[ (int)Math.round((  ((double)x % 360) / 45)) % 8 ]
    

    and you’ve got your problem solved in two lines.

    One note: Modulus won’t work correctly for negative numbers. If our input heading is negative, you’ll need to make it positive first.

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