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Home/ Questions/Q 1028479
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T12:23:40+00:00 2026-05-16T12:23:40+00:00

This won’t work using: $(‘div#menuBar,#goLeftBtn,#goRightBtn’).attr(‘disabled’, true); in the document.ready Any ideas? Thanks! EDIT: My

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This won’t work using:

$('div#menuBar,#goLeftBtn,#goRightBtn').attr('disabled', true);

in the document.ready

Any ideas?
Thanks!

EDIT:
My html is basically like this:

  <div id="floatRight">
       <img src="./images/all_left.png" id="goAllLeft" class="arrow" />
       <img src="./images/left.png" id="goLeft" class="arrow" />
       <img src="./images/right.png" id="goRight" class="arrow"/>
       <img src="./images/all_right.png" id="goAllRight" class="arrow" />
    </div>

I know those aren’t the exact image names in the jquery code above, but that is how all of my img’s are basically set up & for that particular line of code I only need those img’s to be disabled.

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  1. Editorial Team
    Editorial Team
    2026-05-16T12:23:41+00:00Added an answer on May 16, 2026 at 12:23 pm
    $('div#menuBar,#goLeftBtn,#goRightBtn').click(function() { return false; });
    

    will work until you’re ready to activate it.

    Or actually why don’t you just not attach a click event until it’s loaded?

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