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Home/ Questions/Q 7438729
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T10:35:59+00:00 2026-05-29T10:35:59+00:00

This works but I’m not sure why. In function capIn() , in my mind

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This works but I’m not sure why. In function capIn(), in my mind the line $botcap.slideDown("slow") should slide the div down. It slides it up. If I try using .slideUp() nothing happens as if it is trying to slide it down. Can anyone explain this to me?

$(".slide").hover(capIn, capOut);

function capIn(){
    //slide top caption down
    var $topcap = $(this).children(".topcap");
    $topcap.slideDown("slow");

    //slide bottom caption up
    //!! Why does slideDown slide caption up here?
    var $botcap = $(this).children(".botcap");
    $botcap.slideDown("slow")
}

function capOut(){
    //slide top back up
    var $topcap = $(this).children(".topcap");
    $topcap.slideUp("slow");

    //slide bottom back down
    var $botcap = $(this).children(".botcap");
    $botcap.slideUp("slow");
}
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  1. Editorial Team
    Editorial Team
    2026-05-29T10:36:00+00:00Added an answer on May 29, 2026 at 10:36 am

    jQuery’s slideDown and slideUp functions are actually misnomers. As the documentation for slideUp puts it:

    Hide the matched elements with a sliding motion.

    The hiding is achieved by modifying the height of the element; normally, this means that the lower edge of the element appears to slide up, hence the name. However, if the element is anchored at the bottom (e.g. by setting position: absolute and bottom: 0), the height modification will make the top edge appear to slide down.

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